Multi-vector BFloat16 maximum
This instruction determines the maximum of BFloat16 elements of the two or four second source vectors and the corresponding BFloat16 elements of the two or four first source vectors and destructively places the results in the corresponding elements of the two or four first source vectors.
When FPCR.AH is 0, the behavior is as follows:
When FPCR.AH is 1, the behavior is as follows:
This instruction follows SME2 non-widening BFloat16 numerical behaviors corresponding to instructions that place their results in two or four SVE Z vectors.
This instruction is unpredicated.
ID_AA64ZFR0_EL1.B16B16 indicates whether this instruction is implemented.
Variants: FEAT_SME2 && FEAT_SVE_B16B16 (FEAT_SME2 && FEAT_SVE_B16B16)
31 | 30 | 29 | 28 | 27 | 26 | 25 | 24 | 23 | 22 | 21 | 20 | 19 | 18 | 17 | 16 | 15 | 14 | 13 | 12 | 11 | 10 | 9 | 8 | 7 | 6 | 5 | 4 | 3 | 2 | 1 | 0 |
1 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 1 | 0 | 1 | 1 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | ||||||||
size | Zm | opc | Zdn | o2 |
---|
BFMAX { <Zdn1>.H-<Zdn2>.H }, { <Zdn1>.H-<Zdn2>.H }, { <Zm1>.H-<Zm2>.H }
if !IsFeatureImplemented(FEAT_SME2) || !IsFeatureImplemented(FEAT_SVE_B16B16) then EndOfDecode(Decode_UNDEF); constant integer dn = UInt(Zdn:'0'); constant integer m = UInt(Zm:'0'); constant integer nreg = 2;
Variants: FEAT_SME2 && FEAT_SVE_B16B16 (FEAT_SME2 && FEAT_SVE_B16B16)
31 | 30 | 29 | 28 | 27 | 26 | 25 | 24 | 23 | 22 | 21 | 20 | 19 | 18 | 17 | 16 | 15 | 14 | 13 | 12 | 11 | 10 | 9 | 8 | 7 | 6 | 5 | 4 | 3 | 2 | 1 | 0 |
1 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 1 | 1 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | ||||||
size | Zm | opc | Zdn | o2 |
---|
BFMAX { <Zdn1>.H-<Zdn4>.H }, { <Zdn1>.H-<Zdn4>.H }, { <Zm1>.H-<Zm4>.H }
if !IsFeatureImplemented(FEAT_SME2) || !IsFeatureImplemented(FEAT_SVE_B16B16) then EndOfDecode(Decode_UNDEF); constant integer dn = UInt(Zdn:'00'); constant integer m = UInt(Zm:'00'); constant integer nreg = 4;
CheckStreamingSVEEnabled(); constant integer VL = CurrentVL; constant integer elements = VL DIV 16; array [0..3] of bits(VL) results; for r = 0 to nreg-1 constant bits(VL) operand1 = Z[dn+r, VL]; constant bits(VL) operand2 = Z[m+r, VL]; for e = 0 to elements-1 constant bits(16) element1 = Elem[operand1, e, 16]; constant bits(16) element2 = Elem[operand2, e, 16]; Elem[results[r], e, 16] = BFMax(element1, element2, FPCR); for r = 0 to nreg-1 Z[dn+r, VL] = results[r];